ycliper

Популярное

Музыка Кино и Анимация Автомобили Животные Спорт Путешествия Игры Юмор

Интересные видео

2025 Сериалы Трейлеры Новости Как сделать Видеоуроки Diy своими руками

Топ запросов

смотреть а4 schoolboy runaway турецкий сериал смотреть мультфильмы эдисон

Видео с ютуба Applications Of Integration Class 12

12th maths chapter 9 exercise 9.3 question 1 iv-vi applications of integration tn syllabus

12th maths chapter 9 exercise 9.3 question 1 iv-vi applications of integration tn syllabus

Q) Using integration find  the area of the ellipse 𝐱^𝟐/𝟏𝟔+𝐲^𝟐/𝟒=𝟏, included  between the lin

Q) Using integration find the area of the ellipse 𝐱^𝟐/𝟏𝟔+𝐲^𝟐/𝟒=𝟏, included between the lin

Q) Using integration, find  the area of the region bounded by the parabola 𝐲^𝟐=𝟒𝐚𝐱 and

Q) Using integration, find the area of the region bounded by the parabola 𝐲^𝟐=𝟒𝐚𝐱 and

Q) If 𝐀_𝟏 denotes the area of region bounded by 𝐲^𝟐=𝟒𝐱,  x = 1 and x-axis in the first quadran

Q) If 𝐀_𝟏 denotes the area of region bounded by 𝐲^𝟐=𝟒𝐱, x = 1 and x-axis in the first quadran

Q) The area bounded by  the cure y = √𝐱, Y-axis  and between the lines   y = 0 and y = 3 is:

Q) The area bounded by the cure y = √𝐱, Y-axis and between the lines y = 0 and y = 3 is:

Q) The region enclosed between 𝑥=y^2 and 𝑥=4  is divided into two equal parts by the line 𝑥=a.

Q) The region enclosed between 𝑥=y^2 and 𝑥=4 is divided into two equal parts by the line 𝑥=a.

समाकलन का अनुप्रयोग प्रश्नावली 8.1 application of integration exercise 8.1 class 12  ncert solution

समाकलन का अनुप्रयोग प्रश्नावली 8.1 application of integration exercise 8.1 class 12 ncert solution

Q) Sketch the graph of  y=|𝑥+3| and find the areaof the region enclosed by thecurve, 𝑥-axis,

Q) Sketch the graph of y=|𝑥+3| and find the areaof the region enclosed by thecurve, 𝑥-axis,

Q) Sketch the region bounded by the lines  2x + y = 8, y = 2, y = 4 and the y-axis. Hence, obtain

Q) Sketch the region bounded by the lines 2x + y = 8, y = 2, y = 4 and the y-axis. Hence, obtain

Q) In a rough sketch, mark the region bounded by 𝑦=1+|𝑥+1|,𝑥=−2,  𝑥=2 and 𝑦=0. Using integrati

Q) In a rough sketch, mark the region bounded by 𝑦=1+|𝑥+1|,𝑥=−2, 𝑥=2 and 𝑦=0. Using integrati

Q) The area of the region enclosed between the curve 𝑦=𝑥|𝑥|,𝑥-axis,  𝑥=−2 and x=2 is

Q) The area of the region enclosed between the curve 𝑦=𝑥|𝑥|,𝑥-axis, 𝑥=−2 and x=2 is

Q) If the area of the region bounded by the curve 𝐲^𝟐=𝟒𝐚𝐱 and the line x = 4a is 𝟐𝟓𝟔/𝟑 ,

Q) If the area of the region bounded by the curve 𝐲^𝟐=𝟒𝐚𝐱 and the line x = 4a is 𝟐𝟓𝟔/𝟑 ,

Q) The region enclosed between 𝑥=y^2 and 𝑥=4  is divided into two equal parts by the line 𝑥=a.

Q) The region enclosed between 𝑥=y^2 and 𝑥=4 is divided into two equal parts by the line 𝑥=a.

Q) Using integration, find the area of the region bounded by the curve 𝑦=√(4−𝑥^2 ), the lines

Q) Using integration, find the area of the region bounded by the curve 𝑦=√(4−𝑥^2 ), the lines

Q) Find the area of the  region bounded by the  curve 𝟒𝐱^𝟐+𝐲^𝟐=𝟑𝟔  using integration. #class

Q) Find the area of the region bounded by the curve 𝟒𝐱^𝟐+𝐲^𝟐=𝟑𝟔 using integration. #class

Q) The area bounded by  the cure y = √𝐱, Y-axis  and between the lines   y = 0 and y = 3 is:

Q) The area bounded by the cure y = √𝐱, Y-axis and between the lines y = 0 and y = 3 is:

Class 12 Maths Chapter 9 Differential Equations | Revision Class or Pre Board Exam 2025-26

Class 12 Maths Chapter 9 Differential Equations | Revision Class or Pre Board Exam 2025-26

Q) Sketch a graph of 𝑦=𝑥^2.  Using integration, find thearea of the region bounded  by y=9,x=0

Q) Sketch a graph of 𝑦=𝑥^2. Using integration, find thearea of the region bounded by y=9,x=0

Q) The area of the regionbounded by the lines  y=𝑥+1,𝑥=1,𝑥=3 and 𝑥-axis #applicationofintegrals

Q) The area of the regionbounded by the lines y=𝑥+1,𝑥=1,𝑥=3 and 𝑥-axis #applicationofintegrals

Application of Integration

Application of Integration

Следующая страница»

© 2025 ycliper. Все права защищены.



  • Контакты
  • О нас
  • Политика конфиденциальности



Контакты для правообладателей: [email protected]